Considering only the principal values of the inverse trigonometric functions, the value of $$\cot^{-1}(\cot(-11))+10\sin\left(2\cos^{-1}\left(\frac{1}{\sqrt2}\right)\right)+10\sin\left(2\tan^{-1}(2)\right)$$ is
Using principal values, \(\cot^{-1}(\cot(-11))=4\pi-11\). Also, \(\cos^{-1}(1/\sqrt2)=\pi/4\), so \(10\sin(2\cdot\pi/4)=10\sin(\pi/2)=10\). Further, if \(\theta=\tan^{-1}(2)\), then \(\sin(2\theta)=\frac{2\tan\theta}{1+\tan^2\theta}=\frac{4}{5}\). Hence \(10\sin(2\tan^{-1}(2))=8\). Therefore the value is \((4\pi-11)+10+8=4\pi+7\). Thus option (C) is correct.
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